Study for the UCF PCB3063 Genetics Final Exam. Prepare with flashcards and multiple-choice questions, each offering hints and explanations. Ace your exam with confidence!

Meiosis II is the second phase of meiosis, which follows Meiosis I. The primary purpose of Meiosis II is to separate the sister chromatids that were duplicated during the S phase of the cell cycle prior to Meiosis I. During Meiosis II, the two cells produced from Meiosis I undergo a division that resembles mitosis.

In Meiosis I, homologous chromosomes are separated, resulting in two haploid cells, each with duplicated chromosomes (sister chromatids). These two haploid cells then enter Meiosis II. During this phase, each of the haploid cells divides again, separating the sister chromatids into individual chromosomes. The end result of Meiosis II is four haploid cells, each containing a single set of chromosomes. This means that the final product of the meiotic process, starting from one diploid parent cell, is four genetically unique haploid cells, which is crucial for sexual reproduction as these cells can develop into gametes (sperm or eggs).

Thus, the correct answer reflects this end result of four haploid cells produced from the two haploid cells that underwent Meiosis II.